Find the zeroes of the function

y=3x^3-3x

So I factored that to y=3x(x^2-1)

but am not sure about the zeroes. I know that 0 and 1 are zeroes, but am not sure how to get a zeroe from x^2.
Thanks.

Factor it again to get 3x (x+1)(x-1)
The zeroes are where any factor is zero, namely -1, 0 and 1.

wats 2+2

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Four

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