How do you calculate the [H+] and [OH-] for a solution containing 100 mL of 0.05 M HNO3?
1 answer
The same way you calculated H^+ and OH^- from 0.01 perchloric acid in the previous problem. Both HClO4 and HNO3 are strong acids; therefore, they are ionized completely so the (H^+) = (HClO4) or (HNO3).