how do u find the range for this equation

y=x^2+x-2/|x-1|

I went on symbolab, but I dont understand it
thanks

3 answers

x^2+x = x(x+1)
its minimum is at (-1/2, -1/4)
-2/|x-1| is always negative, and causes an asymptote at x=1
So the range is all reals numbers
it says the range is (-3, infinity )
@oobleck it says the range is (-3, infinity )
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