you stated "My equation is 4x^2-8" but
4x^2 - 8 is not an equation.
Did you mean
y = 4x^2 - 8x or f(x) = 4x^2 - 8x ?
If so , then x is the independent variable and y or f(x) is the dependent variable, because the value of y "depends" on what you choose for the x.
The graph of your function will be a parabola which opens upwards and has a vertex at (0,-8)
You could find that by making a table of values and graphing it.
You will see that the domain, your choices for x, is the set of real numbers while the range, the resulting y values, are the set of real number, y ≥ -8
Hi,
My equation is 4x^2-8. I think the independent variable for the equation is 4 and the dependent is x. Is that right? I also have to find the domain and range but I'm not sure how to find those for this equation.
4 answers
Sorry, I meant that the equation is z=4x^2-8. I forgot to add the z if that makes a difference.
Then you are all set. The answer Reiny gave you applies. Either z or y or f(x) is fine on the left.
Okay, thank you.
3 answers