so far i know that you change the x andy
so that gives u y=2^-t/4
x=2^-x/4
then log of 2 is the base , but what do u do with the exponent
how do u find the inverse of
2^-t/4
2 answers
for the expression
y =2 ^ (-t/4), the inverse function is the function which t = f(y). If we solve the above function for t in terms of y:
taking the log of both sides
log(y) = log(2 ^ (-t/4))
log(y) = (-t/4)*log(2)
(log(y))/(log(2))=-t/4
-4*(log(y))/(log(2))=t
y =2 ^ (-t/4), the inverse function is the function which t = f(y). If we solve the above function for t in terms of y:
taking the log of both sides
log(y) = log(2 ^ (-t/4))
log(y) = (-t/4)*log(2)
(log(y))/(log(2))=-t/4
-4*(log(y))/(log(2))=t