How do I simply 4^-1x^0/y^-1

possible answers:

1/4y
4y
y/4
4

I really don't get these- but I think it might be y/4 because you take the negative to the top and the negative to the bottom, right?

2 answers

remember that x^(-a) = 1/x^a
and a^0 - 1 for all a>0

4^-1x^0/y^-1
= (1/4)(x^0)(1/y)
= (1/4)(1)(1/y)
= 1/(4y)

(they should not have written the answer as 1/4y , it would mean (1/4) y )
The way you explained it, I can understand it-the way my teacher explained it-I was still confused
Thank you very much