How do I find the dimensions of a rectangle if the length of the rectangle is 1 yard more than twice its width, and the area of the rectangle is 66 yards^2 .

Answer 1

let's use l and w for the variables

l= 2w + 1
lw= 66 yds. ^2
(2w + 1) w= 66
2w^2 + w= 66
2w^2 + w -66 = 0
(2w -11 ) (w + 6 ) = 0
2w= 11 or w= -6
w= 5.5 is positive so this is our answer!!!

and the length = 2w+1 so simply plug in!
l= 2*(5.5)+ 1
l= 12