How do i find the 12th term of the sequence

36,18,9....

using a formula

3 answers

Matt/John -- please use the same name for your posts.

Use the formula Bobpursley showed you.
This is a GS where a = 36 , r = 1/2
term(n) = a r^(n-1)
term(12) = 36(1/2)^11
= 36(1/2048) = 9/512
THANK YOU SO MUCH REINY.
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