Matt/John -- please use the same name for your posts.
Use the formula Bobpursley showed you.
How do i find the 12th term of the sequence
36,18,9....
using a formula
3 answers
This is a GS where a = 36 , r = 1/2
term(n) = a r^(n-1)
term(12) = 36(1/2)^11
= 36(1/2048) = 9/512
term(n) = a r^(n-1)
term(12) = 36(1/2)^11
= 36(1/2048) = 9/512
THANK YOU SO MUCH REINY.