Question

1. Find the 12th term of the arithmetic sequence 2, 6, 10, … .

2. Solve for the 101st term of the sequence whose 1st term is x-y and d=2x+y-3.

3. In the sequence 2, 6, 10, … , what term has a value of 106?

Answer 1

#1 and #2 are the same type as the ones I just did for you
Give them a try

#3
a=2 , d=4

a+(n-1)d = term(n)
2 + (n-1)(4) = 106
2 + 4n - 4 = 106
4n = 108
n = 27

term(27) = 106

Answer 2

Okay. I think I get it. Thanks for the help.