how do i find all vertical and horizontal asymptotes for the function y= 3x^2-8x+25/x^2+7x-18

Answer 1

vertical asymptotes result when the denominator is zero, so
x^2 + 7x - 18 = (x+9)(x-2)

vertical asymptotes: x = -9 and x = 2

for horizontal asymptotes let x -->∞
then y ---> 3/1 = 3

Horizontal asymtote: y = 3