How do I distribute

(4x^3 - 3x^4) Or (4x^3-3x^4)(4x^3 - 3x^4) the second set is the measurements of a square

1 answer

To distribute (expand) the expression (4x^3 - 3x^4)(4x^3 - 3x^4), you can use the FOIL method, which stands for First, Outer, Inner, Last. Here's how you do it:

(4x^3 - 3x^4)(4x^3 - 3x^4)
First: Multiply the first terms of each set of parentheses:
4x^3 * 4x^3 = 16x^6.

Outer: Multiply the outer terms of each set of parentheses:
4x^3 * -3x^4 = -12x^7.

Inner: Multiply the inner terms of each set of parentheses:
-3x^4 * 4x^3 = -12x^7.

Last: Multiply the last terms of each set of parentheses:
-3x^4 * -3x^4 = 9x^8.

Now, add up all these products:
16x^6 - 12x^7 - 12x^7 + 9x^8
= 16x^6 - 24x^7 + 9x^8.

So, the fully distributed expression is 16x^6 - 24x^7 + 9x^8.
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