How do I differentiate y=x^3(3x+5)^7/2

Answer 1

y=x^3(3x+5)^7/2
y=[ x^3 ] * [ (3x+5)^7/2 ]
dy/dx = [ x^3 ] d [ (3x+5)^7/2 ] / dx + [ (3x+5)^7/2 ] d[x^3]/dx
=[x^3] (7/2)[(3x+5)^5/2] (3) + [ (3x+5)^7/2 ] 3 x^2
= clean up