How do I determine the quantity (g) of pure MgSO4 in 2.4g of MgSO4.7H2O

Answer 1

%MgSO4 in MgSO4.7H2O = [(molar mass MgSO4/molar mass MgSO4.7H2O)]*100 = ?

Then 2.4g x (%MgSO4/100) = ?

Answer 2

THANK YOU! That's what I needed!!