You made a typo. You meant Na2S2O3, I'm sure. So I changed it below and balanced it. By the way, you need to learn to do this on your own, especially since this one is so simple. The four S atoms on the left have an oxidation number of +8 and they change to +10 on the right. The I2 on the left is zero and on the right is -2 for both of the I atoms.
2Na2S2O3 + I2 ---> 2NaI+ Na2S4O6
How do i balance this equation out?
Na2S2O2 + I2 ---> NaI+ Na2S4O6
thank you soo much! =D
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1 answer