2Na2S2O3 + I2 Na2S4O6 + 2NaI
2[S2O3]^2- + I2 ==> [S4O6]^2- + 2I^-
I2 on the left has oxidation state of zero. On the right it is 1- EACH. That is a gain of electrons. A gain of electrons is reduction and that makes I2 the oxidizing agent. [S2O3]^2- is oxidized and is the reducing agent.
Will you please help me write this equation in net ionic form of this equation and oxidation and reduction reaction, and oxidizing and reducing agent
. 2Na2S2O3 + I2 Na2S4O6 + 2NaI
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