how do i answer this. A series RL circuit contains two resistors and two inductors.the resistors are 33 ohms and 47 ohms the inductors have inductive reactances of 60 ohms and 30 ohms. the applied voltage is 120 v. what is the voltage drop on the 33 ohm resister?

Answer 1

Z = R + j X
R = 80 Ohms
X = 90 Ohms

|Z|^2 = 80^2 + 90^2
|Z| = 120 ohms
so i = E/Z = 120/120 = 1 amp

V = i R = 1*33 = 33 V