How do factor a binomial with cubed roots?

cos^3+sin^3/cosx+sinx = 1-sinxcosx

1 answer

Are you trying to prove the identity?
You can use the following algebraic identity:
a^3+b^3=(a+b)(a^2-ab+b^2)
Similar Questions
  1. Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
    1. answers icon 1 answer
  2. Proving identity(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
    1. answers icon 1 answer
    1. answers icon 3 answers
  3. 1) ctgx+cosx=1+ctgx*cosx2) sin^4x+cos^4x=1/2 3) (sinx-cosx)^2=sin2x 4) sin^4x-cos^4x=7/2(sinxcosx) 5)
    1. answers icon 2 answers
more similar questions