How can you solve 9x^4-24^3+16x^2=0?

Answer 1

I will assume your middle term is 24x^3

9x^4 - 24x^3 + 16x^2 = 0
x^2( 9x^2 - 24x + 16) = 0
mmmhh, the first and last terms are perfect squares, could it be ... ???
sure enough:
x^2(3x - 4)^2 = 0

x = 0 , x = ±2/√3

Answer 2

I knw it. . . X ^2 (9x^2 -24x +4 ) =0. . X^2(3x-4)(3x -4) =0. . 3x -4 =0/x^2. 3x-4 =0. . X =4/3 twice