How can the polynomial 6d^4+9d^3-12d^2 be factored?

Answer 1

6d^4+9d^3-12d^2

first, factor out the d^2
d^2(6d^2+9d-12)

Now, how about a 3?
3d^2(2d^2+3d-6)

Now, note that the discriminant is 57, so the roots will contain √57. No rational roots exist. Can't factor it any further using integers.

Answer 2

the answers for unit 4, lesson 2, in connections academy are
b
c
a
d
d

Answer 3

the answers are actually
d
c
a
d
d
yw :)

Answer 4

Zoie is right 100%