Asked by Gabriela
How can I find the horizontal asymptote of:
y=e^x/(2e^x+5)
i know you have to do the limit as x approaches infinity... but that is about all i know...
mulitply the numberator and denominator by e^-x
y= e^0/(2e^0 + 5e^-x)
y= 1/(2 + 5e^-x)
now, take lim as x >> int. Notice the e^-x goes to zero.
y= 1/2 as x approaches zero.
y=e^x/(2e^x+5)
i know you have to do the limit as x approaches infinity... but that is about all i know...
mulitply the numberator and denominator by e^-x
y= e^0/(2e^0 + 5e^-x)
y= 1/(2 + 5e^-x)
now, take lim as x >> int. Notice the e^-x goes to zero.
y= 1/2 as x approaches zero.
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