Asked by Katie
                How do you find the horizontal tangent for the equation f(x)=x^2-3?
Algebraically
            
        Algebraically
Answers
                    Answered by
            bobpursley
            
    take the derivative to get the slope
f'= 2x
so that is the slope of the tangent at any given x
    
f'= 2x
so that is the slope of the tangent at any given x
                    Answered by
            Reiny
            
    f'(x) = 2x
at a horizontal tangent, f'(x) = 0
so 2x=0
x=0
f(0) = 0-3 = -3
so the horizontal tangent is y = -3
    
at a horizontal tangent, f'(x) = 0
so 2x=0
x=0
f(0) = 0-3 = -3
so the horizontal tangent is y = -3
                    Answered by
            Katie
            
    where did you get f(x)=2x??
    
                    Answered by
            Reiny
            
    it is hard to read but it says
f '(x) = 2x , which is short form for the derivative of f(x)
I assumed you know Calculus.
This is a Calculus-type question
    
f '(x) = 2x , which is short form for the derivative of f(x)
I assumed you know Calculus.
This is a Calculus-type question
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