24(x)^8=384
taking log base 2 of each side.
8 log2 x=log2 (384/24)
x= sqrt 2
How can I find the general term of U7=24, U15=384? Please help me with this, thanks in advance!
3 answers
You appear to be missing information. Looking at "Similar Questions" below, it was stated that you had a geometric sequence.
So U7 = 24 ---> ar^6 = 24 and U15 = 384 ---> ar^14 = 384
divide one equation by the other:
ar^14/(ar^6) = 384/24
r^8 = 16
r = ± √2
if r = +√2 , a(8) = 24 , a = 3
and Un = 3(√2)^n
using r = - √2 , we could also have Un = 3(-√2)^n
So U7 = 24 ---> ar^6 = 24 and U15 = 384 ---> ar^14 = 384
divide one equation by the other:
ar^14/(ar^6) = 384/24
r^8 = 16
r = ± √2
if r = +√2 , a(8) = 24 , a = 3
and Un = 3(√2)^n
using r = - √2 , we could also have Un = 3(-√2)^n
www.jiskha.com/questions/302928/find-the-general-term-un-of-the-geometric-sequence-which-has-u7-24-and-u15
3 answers