Asked by Asha
Hoe to simplify this
Log72/75-log50/48+2log25/24
Log72/75-log50/48+2log25/24
Answers
Answered by
Reiny
you have to know the rules of logs
I will use:
log (xy) = log x + log y
log(x/y) = log x - log y
log (x^a) = a log x
Log72/75-log50/48+2log25/24
= log [ (72/75) ÷ (50/48) (25/24)^2 ]
= log [ (72/75(48/50)(625/576) ]
= log [1]
= 0
I will use:
log (xy) = log x + log y
log(x/y) = log x - log y
log (x^a) = a log x
Log72/75-log50/48+2log25/24
= log [ (72/75) ÷ (50/48) (25/24)^2 ]
= log [ (72/75(48/50)(625/576) ]
= log [1]
= 0
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