Asked by yaz

log72-log(2x/3)=0
Answered by Reiny
I hope you are familiar with the standard rules of logs, then...

log72-log(2x/3)=0
log<sub>10</sub> (72 รท 2x/3) = 0

72(3/(2x) = 10^0
216/(2x) = 1
2x = 216
x = 108
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