No, I don't think so.
First, the problem asks for the two balanced half equations. You have given the balanced equation.
Second, the balanced equation you have written is not balanced. For example, Fe = 2 on the left and 6 on the right.
H atoms don't balance.
Cl atoms don't balance.
I atoms don't balance.
and I quit counting.
HIO3 + FeI2 + HCl --> FeCl3 + ICl
(in acidic solution)
Show and label the two balanced half-reactions (oxidation and reduction). Add H2Os, H+s or OH-s as needed.
I just wanted to know if the answer I got is correct
2FeI2 +6HCl +Cl +HIO3-->6FeCl3 +ICl +3H20
2 answers
I don't understand how I am supposed to give two separate half reactions.
1 answer