Vf^2=Vi^2-2ad
solve for d, that is the thickness of the barriers.
Highway safety engineers build soft barriers so that cars hitting them will slow down at a safe rate. A person wearing a seat belt can withstand an acceleration of -300 m/s². How think should barriers be to safely stop a car that hits a barrier at 110 km/h?
3 answers
I had assumed as much but I couldn't find the appropriate formula in the chapter given...
While I'm sure that'll get me the correct answer I get the feeling that I was expected to use another formula.
Anything else come to mind?
While I'm sure that'll get me the correct answer I get the feeling that I was expected to use another formula.
Anything else come to mind?
It would help if you give the context.
Is your chapter on work and energy?
KE = kinetic energy = (1/2)mVi²
Work done
= force * distance
= ma * distance
Equate KE to Work done:
(1/2)mVi² = maD
or D=(1/2)Vi²/a
(Same result as what Mr. Pursley gave)
Is your chapter on work and energy?
KE = kinetic energy = (1/2)mVi²
Work done
= force * distance
= ma * distance
Equate KE to Work done:
(1/2)mVi² = maD
or D=(1/2)Vi²/a
(Same result as what Mr. Pursley gave)
1 answer