CaCO3 ==> CaO + CO2
The process looks ok at first glance but the numbers are wrong. You should have used 14 kg = 14,000 g
Then 14,000/56 = 250
250 mols CaO (I would have used 56.1 for molar mass CaO)
Then 25o mols CaO = 250 mols CaCO3
Then mass CaCO3 = mols CaCO3 x molar mass CaCO3 = 250 x 100.(not 68)
The answer will be in units of grams. Convert to kg if that is needed.
Hi the question asks me to calculate the mass of calcium carbonate that must be decomposed to produce 14kg of calcium oxide.
I think I've gone wrong somewhere, do you write 14000g or 14kg etc, could you help?
I did: Moles CaO=(Mass CaO/Mr CaO)
=1400/56
=25
CaO:CaCO3
1:1
25:25
Mass CaCo= Moles CaCO x Mr CaCO
=25 x 68
=1700
=1.7kg
2 answers
Thank you so much!