Question

Question: "Calculate the theoretical yield of calcium carbonate of you react 2.55g of calcium chloride dihydrate with an excess amount of sodium carbonate."

I got the molar mass of calcium chloride dihydrate which is 131.015 g/mol, but Im not sure how to start the equation for the theoretical yield...

2.55g X ?????

Answer 1

I would use percentage of calcium in CaCl2.2H2O

Percent= molmassCa/131.015

muliply that by 2.55..

Answer 2

you would use Calcium because its the limiting reactant?

So... 40.078/131.015 = .305903

Then... 2.55g X .305903g Ca/1g = the theoretical yield?