Hi, same ques. again

1/3log(base5) 3x + log(base5) 4=3

If the starting is this: log(base5)3x^1/3+log(base5)4=3
What would be the rest?

2 answers

again? Follow the same steps
log(3x)^(1/3) + log4 = 3
1/3 log(3x) + log4 = 3
now proceed as has been shown twice already
Thanks, oobleck
Your calc. made sense
no need to redo it.
Thx..........................................
Similar Questions
  1. Find A so that5log(base5)16807 − 3log(base5)7 = log (base5)A I don't even know how to start this one...should I remove the 5
    1. answers icon 3 answers
  2. Need help with these:Write the expression as a logarithm of a single quality. a) 3log[base5](a) + 4log[base5](b) -
    1. answers icon 2 answers
    1. answers icon 3 answers
  3. 1/3log(base5) 3x + log(base5) 4=3what I meant is: 1/3=one-third ,log5= log(base5)
    1. answers icon 1 answer
more similar questions