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Find A so that


5log(base5)16807 − 3log(base5)7 = log (base5)A

I don't even know how to start this one...should I remove the 5 and 3 in front of the logs?

3 answers

log5 16807^5 - log57^3 = log5A
log5 (16807^5/7^3) = log5A

A = 16807^5 / 7^3
= 49(16807)^4
= appr 3.91 x 10^18
oh right you just have to factor out the logbase5...thank you
You are NOT factoring it out
You are saying that if
log x = log y
then x = y
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