Hi

Question

i need to find x in 9^(2x-6)=6^(8x-5)
So what i did was:
3^(4x-12)=6^(8x-5)
log3(3)^(4x-12)=log3(6)^(8x-5)
4x-12=(8x-5)log3(6)

now i'm stuck. and i actually feel that the whole thing is wrong. help, pls

Answer 1

9^(2x-6)=6^(8x-5)
(2x-6) log9 = (8x-5)log6
(2log9)x - 6log9 = (8log6)x - 5log6
x = (6log9 - 5log6)/(2log9 - 8log6)

you can massage that a few ways, but that's the idea

Answer 2

thanks!