Hi, how do I calculate how many grams of unknown diprotic acid are needed to make 150mL of 0.750N (normal) solution?

Question

and to make 125mL of 0.500M (molar) solution?

we have 0.5000M of NaOH..

Please help me...

Answer 1

a).
How many equivalents do you need? THat is L x N = 0.150 x 0.750 = ?
grams = equivalent weight x equivalents.
You don't list the diprotic acid; however, the equivalent weight of the diprotic acid = molar mass/2.