The sum of the heats GAINED is zero. (one will have a negative heat gained).
Heatgainedwater+heatgainedAl=0
mass*cw*(Tf-28)+2.05kg*Cal(Tf-tial)=0
put in the specific heat constants, Tfinal, and solve for mass.
Hi! Help me please, thank you so much.
What mass of water at 28.0 °C must be allowed to come to thermal equilibrium with a 2.05-kg cube of aluminum initially at 1.50 102 °C to lower the temperature of the aluminum to 54.8 °C? Assume any water turned to stream subsequently recondenses.
1 answer
1 answer