Is the rate 1.7*10^-3 mol. H2O2/s or 1.7*10^-3 mol. O2/s ?? It makes a difference.
Multiply the rate by 60 s to get moles of H2O2 or O2 formed. If the rate is moles H2O2/s, you must divide the moles you get by 2 to get moles of O2.
Next, use the Ideal Gas Law, PV = nRT, to get V in liters.
Finally, convert the liters to mLs.
Hi can someone please help with this question, or atlest direct me in the right direction. Please and thank you.
The initial rate of reaction
H2O2(aq) --> H2O (l) + 1/2 O2(g)
is found to be1.7*10^-3 M/s . Assume that this rate holds for 2 minutes. Start with 165ml of 1.55M H2O2 (aq) at t=0 .
How many milliliters of O2(g) measured at 24 degress celsius and 759 , are released from solution in the first minute of the reaction?
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