Hi.
1. I have a right triangle here. I know that I am to use the Pythagorean Theorem: a^2 + b^2 = c^2.
In this case, side a is (x + 4) and b is x. The hypotenuse is 4 + (x + 4)
So here we have the equation: (x + 4)^2 + x^2 = 4 + (x + 4)^2.
I need to find the length of a (the short leg), the length of a, and the length of the hypotenuse. I have tried several times to work out this equation with no luck.
2. I have another right triangle here. I know that I am to use the Pythagorean Theorem: a^2 + b^2 = c^2.
In this case, side a is x and b is 1/2x + 11. The hypotenuse is 2x + 1. I need to find the length of a (the short leg), the length of a, and the length of the hypotenuse.
x^2 + (1/2x + 11)^2 = (2x + 1)^2
Thank you!
3 answers
# 2: * I need to find the length of a (the short leg), the length of b, and the length of the hypotenuse.
just curious what grade is this math
This is Algebra. Haha.. You can take algebra between 8th and 11th grade. Something like that.. Not really a grade thing.. Just a subject. Why do you ask?
1 answer