hey so this is for rate law if the first step is the slow step. it is also an equilibrium. I just want to check if this is right. [Acetophenone]+[Ethoxide] k-1 [Intermediate]+[Ethanol] Just want to make sure this will be the rate law: k1/k-1 [Acetophone][Ethoxide] or do I leave out k-1?

hey so this is for rate law if the first step is the slow step. it is also an equilibrium. I just want to check if this is right.

[Acetophenone]+[Ethoxide]<-k1-->
k-1
[Intermediate]+[Ethanol]

Just want to make sure this will be the rate law: k1/k-1 [Acetophone][Ethoxide]

or do I leave out k-1?

Ask a New Question or answer this question.

Similar Questions

The experimentally determined rate law for the reactionH2 + NO --> ½N2 + H2O is Rate = k[H2][NO]2. Is the mechanism below
1. 0 answers
Step 1 : A + B → C + E (slow)Step 2 : B + E → D (fast) Predict the rate law if step 1 is slow.
1. 1 answer
Step 1 : A + B → C + E (slow)Step 2 : B + E → D (fast) Predict the rate law if step 1 is slow.
1. 1 answer
What are the order of operations? * 1 point Parenthesis Multiplication Addition Division Exponents Subtraction 1st step 2nd step
1. 1 answer