The experimentally determined rate law for the reaction �

Question

H2 + NO --> ½N2 + H2O is Rate = k[H2][NO]2. �

Is the mechanism below possible?�

Step 1: H2 + NO --> N + H2O Slow�
Step 2: N + NO -->N2 + O Fast�
Step 3: O + H2 --> H2O Fast

1. Yes, because the slow step reactants are the same as the overall reaction

2.Yes, because it is consistent with the rate law.

3.No, because it is not consistent with the rate law

I was thinking that the answer was #2, but Im not exactly sure why!