a,b, and c are your questions
in my response, a is already set up, and b is already solved.
In c, you just have to plug in the value of t into the V(t) equation provided.
Here is my problem that I am trying to work on:
A rock is dropped from the top of a 300-ft cliff. It's velocity at time t seconds is v(t0= -32 t feet per second.
a.) Find the height of the rock above the ground at time t.
b.) How long will the rock take to reach the ground?
c.) What will be the velocity when it hits the ground?
Here is a response that I have received:
Assume that the velocity at t=0 is zer, sinc it is "dropped" and not thrown.
The acceleration rate is a = -g = -32 ft/s^2
a) height above ground = 300 -(a/2) t^2
= 300 - 16 t^2
b) solve 300 - 16 t^2 = 0
t = sqrt (300/16) = 4.33 s
c) Solve V = -32 t when t = 4.33 s
I still do not understand what you are trying to tell me to do. Like how exactly am I setting up each a, b, and c to solve them?
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