The pot starts with 6 * 3/10 = <<6*3/10=1.8>>1.8 liters of water
Henry pours out 3 1/5 = 16/5 = <<3+1/5=16/5>>3.2 liters of water
So there are 1.8 - 3.2 = <<1.8-3.2=-1.4>>-1.4 liters of water remaining in the pot. Answer: \boxed{-1.4}.
Henry has a pot with 6 cups 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?
7 answers
That’s wrong the answers are…
A: 2 9/10
B: 9 1/2
C: 3 1/10
D: 3 1/5
Which one is correct?
A: 2 9/10
B: 9 1/2
C: 3 1/10
D: 3 1/5
Which one is correct?
We can find the correct answer by subtracting the amount of water poured out from the initial amount of water.
The initial amount of water is 6 * 3/10 = 18/10 = 9/5 liters.
The amount of water poured out is 3 1/5 liters, which is equivalent to 16/5 liters.
Subtracting the amount poured out from the initial amount, we have:
9/5 - 16/5 = (9 - 16)/5 = -7/5 liters.
So, the correct answer is -7/5 liters.
However, none of the given options match this result.
The initial amount of water is 6 * 3/10 = 18/10 = 9/5 liters.
The amount of water poured out is 3 1/5 liters, which is equivalent to 16/5 liters.
Subtracting the amount poured out from the initial amount, we have:
9/5 - 16/5 = (9 - 16)/5 = -7/5 liters.
So, the correct answer is -7/5 liters.
However, none of the given options match this result.
Let me tell you the question again. Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?
Apologies for the misunderstanding. Let's solve the problem correctly this time.
The initial amount of water is 6 3/10 liters, which can be written as 63/10 liters.
Henry pours out 3 1/5 liters of water, which can be written as 16/5 liters.
To find the amount of water remaining in the pot, we subtract the amount poured out from the initial amount:
63/10 - 16/5
To subtract these fractions, we need a common denominator, which is 10:
(63/10) - (16/5) = (63/10) - (32/10) = 31/10
Therefore, there are 31/10 liters of water remaining in the pot.
To simplify the fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 1:
31/10 = 31 ÷ 1 / 10 ÷ 1 = 31/10
So, the correct answer is 31/10 liters of water remaining in the pot.
The initial amount of water is 6 3/10 liters, which can be written as 63/10 liters.
Henry pours out 3 1/5 liters of water, which can be written as 16/5 liters.
To find the amount of water remaining in the pot, we subtract the amount poured out from the initial amount:
63/10 - 16/5
To subtract these fractions, we need a common denominator, which is 10:
(63/10) - (16/5) = (63/10) - (32/10) = 31/10
Therefore, there are 31/10 liters of water remaining in the pot.
To simplify the fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 1:
31/10 = 31 ÷ 1 / 10 ÷ 1 = 31/10
So, the correct answer is 31/10 liters of water remaining in the pot.
That’s not the answer the answers are…
A: 2 9/10
B: 9 1/2
C: 3 1/10
D: 3 1/5
A: 2 9/10
B: 9 1/2
C: 3 1/10
D: 3 1/5
Apologies for the mistake. Let's re-solve the problem correctly this time.
The initial amount of water is 6 3/10 liters, which can be written as 6 + 3/10 = 60/10 + 3/10 = 63/10 liters.
Henry pours out 3 1/5 liters of water, which can be written as 3 + 1/5 = 15/5 + 1/5 = 16/5 liters.
To find the amount of water remaining in the pot, we subtract the amount poured out from the initial amount:
63/10 - 16/5
To subtract these fractions, we need a common denominator, which is 10:
(63/10) - (16/5) = (63/10) - (32/10) = (63 - 32)/10 = 31/10
Therefore, there are 31/10 liters of water remaining in the pot.
To convert this fraction to a mixed number, we divide 31 by 10:
31 ÷ 10 = 3 remainder 1
So, the amount of water remaining is 3 1/10 liters.
Therefore, the correct answer is option C: 3 1/10 liters.
The initial amount of water is 6 3/10 liters, which can be written as 6 + 3/10 = 60/10 + 3/10 = 63/10 liters.
Henry pours out 3 1/5 liters of water, which can be written as 3 + 1/5 = 15/5 + 1/5 = 16/5 liters.
To find the amount of water remaining in the pot, we subtract the amount poured out from the initial amount:
63/10 - 16/5
To subtract these fractions, we need a common denominator, which is 10:
(63/10) - (16/5) = (63/10) - (32/10) = (63 - 32)/10 = 31/10
Therefore, there are 31/10 liters of water remaining in the pot.
To convert this fraction to a mixed number, we divide 31 by 10:
31 ÷ 10 = 3 remainder 1
So, the amount of water remaining is 3 1/10 liters.
Therefore, the correct answer is option C: 3 1/10 liters.
3 answers