Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?(1 point)

Question

Responses

Answer 1

To find the remaining amount of water, we need to subtract the amount poured out from the original amount.

6 3/10 - 3 1/5

First, let's convert both mixed numbers to improper fractions.

6 3/10 = (6 * 10 + 3)/10 = 63/10
3 1/5 = (3 * 5 + 1)/5 = 16/5

Now, subtract the fractions:

63/10 - 16/5

To subtract these fractions, we need a common denominator. The least common multiple of 10 and 5 is 10. So, let's convert both fractions to have a denominator of 10.

(63/10) * (2/2) = 126/20
(16/5) * (2/2) = 32/10

Now we can subtract:

126/20 - 32/10 = (126 - 32)/20 = 94/20

Simplifying the fraction, we get:

94/20 = 47/10

Therefore, there are 47/10 liters of water remaining in the pot.

Answer 2

A. 3 1/5
B. 3 1/10
C. 2 9/10
D. 9 1/2

Answer 3

To find the remaining amount of water, we subtract the amount poured out from the original amount.

Original amount of water: 6 3/10 liters
Amount poured out: 3 1/5 liters

To subtract mixed numbers, we need to convert them to improper fractions.

6 3/10 = (6 * 10 + 3) / 10 = 63/10
3 1/5 = (3 * 5 + 1) / 5 = 16/5

Now let's subtract the fractions:

63/10 - 16/5 = (63 - (16 * 2)) / 10 = (63 - 32) / 10 = 31/10

So the remaining amount of water in the pot is 31/10 liters.

But let's convert it back to a mixed number:

31/10 = 3 whole and 1/10

Therefore, the correct answer is B. 3 1/10