isn't 7^-2 = 1/49?
if so, log7 (1/49)=-2
help in solving log7 (1/49) = x
2 answers
log7 (1/49) = x is equivalent to
7^x = 1/49 by the definition of logarithms, thus ...
7^x = 49^-1
7^x = (7^2)^-1
x = -2
7^x = 1/49 by the definition of logarithms, thus ...
7^x = 49^-1
7^x = (7^2)^-1
x = -2
2 answers