help in solving log7 (1/49)

Solve:2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2) = log7 5x = log7 + 6(log2) x = (log7 + log2^6) / 5 And textbook
1. 2 answers
2. asked by Anonymous
3. 1,221 views
help in solving log7 (1/49) = x
1. 2 answers
2. asked by Lisa
3. 1,495 views
these are some problems i do not get any help is appreciated. These are copied exactly from the worksheet so i don't think i
1. 6 answers
2. asked by johnica martin
3. 704 views
Expand each logarithm.log 7(3x-2)^2 log(3xyz)^2 Thanks in advance. One. log7(3x-2)^2= log7 + 2 log (3x-2)
1. 0 answers
2. asked by Amber
3. 663 views
These are Two problems that I am having difficulty with.Write as a single logarithm. Assume all variables represent positive
1. 1 answer
2. asked by Anonymous
3. 690 views
Log7x=log7 4+log7 3 please help I can not anderstand thanks
1. 3 answers
2. asked by Heather
3. 623 views
Can someone see if I got these correct?1. Solve log5 x = 3. x = 125 2. log3 (x - 4) > 2. x > 13 3. Evaluate log7 49. log7 49 = 2
1. 2 answers
2. asked by Nikki
3. 1,117 views
Solve for x in the following equations. (4 marks)log3(x - 5) + log3(x + 3) = 2 <--- both log3.. 3 is subscript log7x + log7(x -
1. 1 answer
2. asked by james
3. 664 views
log 5 �ã5log7 (1/49)
1. 1 answer
2. asked by sky
3. 619 views
(2*log7 16)/(log3(√10+1)+log3(√10-1)log7 2
1. 3 answers
2. asked by Stasy
3. 5,969 views