First write and balance the equation.
CH3COOH + NaOH ==> CH3COONa + H2O
moles NaOH = M x L = 0.166*0.25 = ??moles
Look at the equation and you know moles NaoH = moles CH3COOH.
g CH3COOH = moles CH3COOH x molar mass CH3COOH.
That # grams is in 50 mL; you want the # grams in 100 mL. That will be the %CH3COOH m/v
Help! I need to do this review question and don't know where to start !
The label on a bottle of vinegar claims that the bottle conatins 5% (m/v) of acetic acid. In order to test this claim, a 50ml sample is titrated with sodium hydroxide. 166ml of 0.25 mol/l is added when the indictor turns pink. What is the concentration of acetic acid in the vinegar?
4 answers
Okay! Thank you for the help !
I got 6.80932 % ... is that correct?
I got 6.80932 % ... is that correct?
I don't think so. Post your work and I'll find your error.
Nero-Crush on You