HELP!!!! I don't know how to do the trig identity with this problem

Question

csc^4 x-cot^4x= Csx^2 x + cot^2x

Answer 1

recall that a^2 - b^2 = (a+b)(a-b)

csc^4 - cot^4 = (csc^2 - cot^2)(csc^2 + cot^2)

if you recall that csc^2 = 1 + cot^2 the rest is downhill. . .