I will do one for you.
You try some of the others and let me know what you got.
#8
csc x = -13/5, then
sin x = -5/13
so by CAST, angle x is in either III or IV
construct a right-angled triangle with the side opposite angle x as 5 and hypotenuse 13 (sin ß = opp/hyp)
By Pythagoras the adjacent side is 12
so in III, (x is appr. 202.62º)
sin x = -5/13
cos x = -12/13
sec x = -13/12
tan x = 5/12
cot x = 12/5
in IV, (x is appr. 337.38º)
sin x = -5/13
cos x = 12/13
sec x = 13/12
tan x = -5/12
cot x = -12/5
Use the trig Identities to find the other 5 trig functions.
Problem
7.)Tan(90-x)=-3/8
8.)Csc x=-13/5
9.)Cot x=square root of 3
10.)Sin(90-x)=-.4563
11.)Sec(-x)=4
12.)Cos x=-.2351
I need HELP!
3 answers
Would #7 be Sin- 3 over square root of 73 Cos- 8 over square root of 73 Tan- -8/3 Csc- square root of 73 over 3 Cot- -3/8
sin x =4/5 and cos y = 5/3
sin x = 4/5
cos x = 3/5
soc^2 x = 5/3- answer
sin x = 4/5
cos x = 3/5
soc^2 x = 5/3- answer