Problem 1
r goes 45.1 m in t seconds at 40*10^3/3600 or 11.1 m/s
so t = 45.1 /11.1
t = 4.06
in the same t seconds the green car goes
175 = Vo t + .5 a t^2
175 = Vo (4.06) + .5 a (4.06)^2
175 = 4.06 Vo + 8.25 a
Problem 2
t = 78.1/22.2 = 3.52 s
142 = Vo (3.52) + .5 a (3.52)^2
142 = 3.52 Vo + 6.20 a
so you have
175 = 4.06 Vo + 8.25 a
142 = 3.52 Vo + 6.20 a
Two linear equations, two unknowns. I think you can take it from there.
hello sorry once again...this will be my last question...i promise...but here is the question....
A red car and a green car, identical except for the color, move toward each other in adjacent lanes and parallel to an x axis. At time t = 0, the red car is at xr = 0 and the green car is at xg = 220 m. If the red car has a constant velocity of +20 km/h, the cars pass each other at x = 45.1 m, and if it has a constant velocity of +40 km/h, they pass each other at x = 78.1 m.
a) What is the initial velocity of the green car?
b) What is the acceleration of the green car?
i know dat t=0 and xr= 0 while
for xg=220m
how should i start...tnx once again for all the help :)
1 answer