Asked by Jesse
hello, so i'm doing a physics project where I have found the following equation for centripetal force: Fcent=mrù^2
Where f= centripetal force
m=mass
r=radius
ù=angular velocity
my question is to make centripetal force greater, does that mean mass, radius and angular velocity have to be greater too? because that is what I'm interpreting from the following equation.
Where f= centripetal force
m=mass
r=radius
ù=angular velocity
my question is to make centripetal force greater, does that mean mass, radius and angular velocity have to be greater too? because that is what I'm interpreting from the following equation.
Answers
Answered by
Jesse
update: for the u, I don't what happen to it but its supposed to be an omega sign--I guess the formatting got a little messed up
Answered by
John
As long as there is no denominator in the formula, each of your variables is directly related to centripetal force.
This means if m, r or angular velocity are increased, then Fcent will increase.
Due to the squaring on one variable, an increase in that variable will have a larger influence on Centripetal force.
This means if m, r or angular velocity are increased, then Fcent will increase.
Due to the squaring on one variable, an increase in that variable will have a larger influence on Centripetal force.
Answered by
Damon
m r omega^2
is exactly the same as
m v^2/r
but the second may be an easier way to understand it.
remember v = omega * r
where v is tangential velocity (along the circumference if a circle)
is exactly the same as
m v^2/r
but the second may be an easier way to understand it.
remember v = omega * r
where v is tangential velocity (along the circumference if a circle)
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