Just use one of the 3 basic rules of logarithms
y = x^a , (a for alpha)
take ln of both sides:
ln y = ln (x^a)
ln y = a(lnx)
lnx = (ln y)/a
Hello! It’s been quite awhile since I’ve touched algebra, but would appreciate any guidance you may offer for this prompt:
“Y= X^(alpha); solve for ln x”
I understand this has to do with natural logarithms, but does the base rule apply here and ln of x would be alpha?
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