e^.2x = 75/(30*16)
.2x ln e = ln (75/480)
but ln e = 1
.2 x = ln (75/480)
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8^tan x * ln 8 * (1/sec^2 x)
Hello, I really need help on these two homework problem. ><
In problem #1, I believe it is related to the exponential functions and their derivatives section...in Calculus II? So, surely there should be a ln in the solution as well?
I would like a step by step process and explanation on how to solve these functions. I cannot seem to understand how to go about them correctly..
I would greatly appreciate it.
Thank you.
1) Solve the equation:
75/(16e^0.2x) = 30
2)Differentiate the function:
h(x) = 8^tanx
3 answers
Thank you so much.
Although for problem number 1, I realized that I inputted it incorrectly (having problems with my + key).
It is actually:
75/(1+6e^0.2x) = 30
Would I still solve it the same way but subtract 1 to the other side?
Although for problem number 1, I realized that I inputted it incorrectly (having problems with my + key).
It is actually:
75/(1+6e^0.2x) = 30
Would I still solve it the same way but subtract 1 to the other side?
make that sec^2 x and not 1/sec^2 x