you are right, it does not factor over the rational numbers.
here is a webpage that solves cubics for you, just enter the constants
it gave me 1 irrational root and 2 complex roots.
Hello, I have tried solving this using the rational roots theorem and none of the roots seem to be working. I'm trying to figure out where I went wrong.
3x^3 -2x^2 - 7x - 4 = 0
4 answers
Thanks for the help. However, I don't see the webpage you were speaking of.
how silly of me
http://www.1728.com/cubic.htm
http://www.1728.com/cubic.htm
Thanks!